Result Steganography

The images that have information are:

code

letter 

url

The content of each one are: a letter, an url and the code of my program.

code:

from sys import argv
from PIL import Image

def openFile(fileName):
    f = open(fileName, 'r')
    mensaje = list()
    for line in f:
        mensaje.append(line)
    f.close()
    return "".join(mensaje)

def setMsn(mensaje):
    m2 = list()
    mensaje = list(mensaje)
    
    for i in mensaje:
        u = bin(ord(i))[2:].zfill(8)
        for j in u:
            m2.append(j)
    return m2

def getMsn(mensaje):
    m2 = list()
    a = 1
    b = ''
    for i in mensaje:
        b = b+i
        if(a%8 == 0):
            m2.append(chr(int(b,2)))
            b = ''
                       
        a = a + 1
    return "".join(m2)

def pixelF(m2, v, count):
    if(v[7:8] != m2[count]):
        v = v[:7]+m2[count]
    else:
        v = v
    return int(v, 2)
            
def openImage(fileName, m2):
    im = Image.open(fileName)
    rgb = im.convert('RGB')
    c = 0

    while c != len(m2)-1:
        for i in range(0, im.size[0], 3):
            for j in range(im.size[1]):
                b = rgb.getpixel((i, j))[2]
                v = bin(b)[2:].zfill(8)

                w = pixelF(m2, v, c)

                r = rgb.getpixel((i, j))[0]
                g = rgb.getpixel((i, j))[1]

                d = tuple([r,g,w])
                im.putpixel((i,j),d)
                if(c == len(m2)-1): break
                c = c+1
    im.save(str(2)+fileName, "PNG")

def decodeM(fileName):
    im = Image.open(fileName)
    rgb = im.convert('RGB')
    arrayRGB = list()

    for i in range(0, im.size[0], 3):
        for j in range(im.size[1]):
            b = rgb.getpixel((i, j))[2]
            v = bin(b)[2:].zfill(8)
            arrayRGB.append(v[7:8])
    return arrayRGB

def main():

    mensaje = openFile(argv[1])
    mensaje = setMsn(mensaje)
   
    imagen = argv[2]
    print imagen
    w = openImage(imagen, mensaje)

    m2 = decodeM(str(2)+imagen)
    print getMsn(m2)
    
main()

The code take 2 parameters, the name of the file that contains the information and the name of the image to save.
> criptoImage.py fileInformation.txt image.png > dInformation.txt

To decrypt we can use the next code:
 

from sys import argv
from PIL import Image

def getMsn(mensaje):
    m2 = list()
    a = 1
    b = ''
    for i in mensaje:
        b = b+i
        if(a%8 == 0):
            m2.append(chr(int(b,2)))
            b = ''
                       
        a = a + 1
    return "".join(m2)

def decodeM(fileName):
    im = Image.open(fileName)
    rgb = im.convert('RGB')
    arrayRGB = list()

    for i in range(0, im.size[0], 3):
        for j in range(im.size[1]):
            b = rgb.getpixel((i, j))[2]
            v = bin(b)[2:].zfill(8)
            arrayRGB.append(v[7:8])
    return arrayRGB

def main():

    m2 = decodeM(str(1)+imagen)
    print getMsn(m2)
    
main()

This code only takes the name of the image